x^2/3+2x=1+x

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Solution for x^2/3+2x=1+x equation: 


x in (-oo:+oo)

(x^2)/3+2*x = x+1 // - x+1

(x^2)/3+2*x-x-1 = 0

1/3*x^2+x-1 = 0

DELTA = 1^2-(-1*1/3*4)

DELTA = 7/3

DELTA > 0

x = ((7/3)^(1/2)-1)/(1/3*2) or x = (-(7/3)^(1/2)-1)/(1/3*2)

x = 3/2*((7/3)^(1/2)-1) or x = -3/2*((7/3)^(1/2)+1)

x in { -3/2*((7/3)^(1/2)+1), 3/2*((7/3)^(1/2)-1) }

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